f(x)=4x^2-3x+1 dan g(x)=sin x,maka nilai dari (f 0 g).(v/6)?

f(x) = 4x²-3x+1
g(x) = sin x
(fog)(π/6) = f(g(π/6))

g(π/6) = sin 180°/6
g(π/6) = sin 30°
g(π/6) = ½

f(g(π/6)) = f(½)
f(½) = 4(½)² -3(½) +1
f(½) = 1 -3/2 +1
f(½) = 2 -3/2
f(½) = ½

(fog)(π/6) = f(g(π/6)) = f(½) = ½