carilah fungsi F, jika f'(x)=1-2x dan f(3)=4

Integral

f(x) = ∫ f'(x) dx
f(x) = ∫ 1 - 2x dx
f(x) = x - x² + c
f(3) = 4 --> (3) - (3)² + c = 4
3  -  9 + c = 4
-6 + c = 4
c = 10

f(x)=  - x² + x + 10

Materi Integral

Integralkan f'(x)
f(x) = int (1 -2x) dx = x - x^2 +C
f(3) = 4 = 3 - 3^2 + C
4 = -6 + C
C = 10.
Berarti
f(x) = x - x^2 + 10