(3 per 3 pangkat x - 2 )pangkat 2 = akar tiga dari 1 per 9

Persamaan eksponen

[3/(3ˣ⁻²)]² = ∛(1/9)
[(3)¹⁻⁽ˣ⁻²)]² = (3⁻²)¹/³ = (3⁻¹/³)²


1 - (x- 2)=   -(1/3)
1 - x + 2 = - 1/3 ...kalikan 3
3 - x + 6 = - 1
-x + 9 = - 1
-x = - 1 - 9
x = -10/-1
x = 10