Matematika

Pertanyaan

(1/3)^3x-9=(1/27)^4x+1

1 Jawaban

  • (1/3)^(3x - 9) = (1/27)^(4x + 1)
    (1/3)^(3x - 9) = ((1/3)^3)^(4x + 1)
    3x - 9 = 3(4x + 1)
    3x - 9 = 12x + 3
    12x - 3x = -9 - 3
    9x = -12
    x = -12/9
    x = -1 3/9
    x = -1 1/3

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