integral 2/akar 3 X dx

integral

∫ 2/√(3x) dx  = ∫ 2/ (√3  x¹/² ) dx
= ∫ (2/√3) . x⁻¹/² dx
=  (2/√3) .(2) x¹/²  + c
= (4/√3) √x  + x
= 4/3  √(3x)  + c 
(di lampiran)

∫2/√(3x) dx
= 2∫(3x)^(-1/2) dx
= 2 . 3^(-1/2) . 1/(1/2) . x^(1/2) + c
= 4/√3 . √x + c
= (4/3)√(3x) + c