tolong dijawab please!!!!!!!

integral tak tentu
∫ a xⁿ dx  =  a/(n+1)  xⁿ⁺¹

a. ∫ 4x³ dx = 4/4 x⁴ + c = x⁴ + c

b. ∫ 4x⁴ - 4x³ + 3x² - 6x dx =  4/5 x⁵ - 4/4 x⁴ + 3/3 x³ - 6/2 x² + c
= 4/5 x⁵ - x⁴ + x³ - 3x² + c

c.  ∫ 6x⁸ dx =  6/9 x⁹ + c = 2/3  x⁹ + c

d. ∫ (2x -3)²  dx = ∫ 4x² - 12x + 9 dx
= 4/3 x³ - 12/2 x² + 9x + c
= 4/3 x³ - 6x² + 9x + c

e. ∫ x² ( x + 6) dx  = ∫ x³ + 6x²  dx
= 1/3 x³ + 6/3 x² + c
= 1/3 x³ +  2x² + c

f. ∫ 1/x³ dx = ∫ x⁻³ dx =  1/(-2) x⁻² + c
=  - 1/2 x⁻² + c
= -1/(2x²) + c
.