A. 12√27-2√48+√75= b.(3√5-√50) ×√160= yang ke c ada per nya jadi cerita aja ya.

a) 12√9.3 - 2√16.3 + √25.3
= 12×3√3 - 2×4√3 + 5√3
= 36√3 - 8√3 + 5√3
= 33√3

b) (3√5 - √50)×√160
(3√5 - √25.2) × √16.10
= (3√5 - 5√2) × 4√10
= 3×4√(5×10) - 4×5√(2×10)
= 12√50 - 20√20
= 12√25.2 - 20√4.5
= 12×5√2 - 20×2√5
= 60√2 - 40√5

c) {√63/√28} × (√7 + √112)
= √(63/28) × (√7 + √16.7)
= √(9/4) × (√7 + 4√7)
= 3/2 × 5√7
= 15/2 √7

a)
12V27 - 2V48 + V75
= 12V(9 × 3) - 2V(16 × 3) + V(25 × 3)
= (12 × 3)V3 - (2 × 4)V3 + 5V3
= 36V3 - 8V3 + 5V3
= 33V3

b)
(3V5 - V50) × V160
= (3V5 × V160) - (V50 × V160)
= 3V800 - V8000
= 3V(400 × 2) - V(1600 × 5)
= (3 × 20)V2 - 40V5
= 60V2 - 40V5

c)
V63/V28 × (V7 + V112)
= V(9×7)/V(4×7) × (V7 × V(16×7))
= 3V7/2V7 × (V7 + 4V7)
= 3/2 × 5V7
= (15/2)V7