Matematika

Pertanyaan

tolong dibantu yaa.. makasih:)
tolong dibantu yaa.. makasih:)

1 Jawaban

  • 3^(2x + 1) + 3^(2x + 2) = 4 ^3√(9^(x - 2))
    3^2x . 3^1 + 3^2x . 3^2 = 4 . 9^(x - 2)/3
    9^x . 3 + 9^x . 9 = 4 . 9^(x - 2)/3
    9^x . (3 + 9) = 4 . 9^(x - 2)/3
    9^x . 12 = 4 . 9^(x - 2)/3
    9^x / 9^(x - 2)/3 = 4/12
    9^(x - (x - 2)/3) = 1/3
    9^(3x - x + 2)/3 = 3^-1
    9^(2x + 2)/3 = 3^-1
    3^2(2x + 2)/3 = 3^-1
    2(2x + 2)/3 = -1
    4x + 4 = -3
    4x = -7
    x = -7/4