Tlg jawab no 7 makasih

7(8^p) = 9(5^q)
5^q = 7(8^p) / 9
5^q = 7(2^3p) / 9

7(16^(p + 1)) = 12(5^q)
7(2^4(p + 1)) = 12 . 7(2^3p)/9
2^(4p + 4) = 12 (2^3p) / 9
2^(4p + 4) / 2^3p = 12/9
2^(4p + 4 - 3p) = 4/3
2^(p + 4) = 4/3
2^p . 2^4 = 4/3
2^p . 16 = 4/3
2^p = (4/3) / 16
2^p = 4/48
2^p = 1/12

^ pangkat
7(8^p) = 9(5^q)
5^q = 7/9 (8^p)

7(16^(n+1)) = 12(5^q)
substitusi 5^q dengan persamaan pertama
7(16^n . 16) = 12{7/9(8^p)}
7×16(16^n) = 12×7/9(8^p)
7×16(8.2)^n = 28/3(8^p)
7×16(8^n . 2^n) = 28/3(8^p)
(8^n . 2^n)/8^n = 28/(3×7×16)
2^n = 1/12