Fraksi mol larutan 36 gram glokosa dalam 90 gram air Ar c= 12g/mol, Ar o=16 g/mol, Ar H= 1 g/mol

Mr glukosa = 180
Mr air = 18

mol glukosa (n) = massa / Mr
n = 36 / 180
n = 0,2

mol air (x) = massa / Mr
x = 90 / 18
x = 5

[tex]X_{glukosa} = \frac {n}{n + x}[/tex]
[tex]X_{glukosa} = \frac {0,2}{0,2 + 5} \approx 0,0385[/tex]