F(x)=(2x-1)²(x+2),maka f'(x)=

Turunan

f(x)= (2x-1)² (x+2)

cara 1
f = u. v
u = (2x-1)²  --> u' =  2(2x -1)(2) = 4(2x-1)= (8x -4)
v = x + 2  --> v' = 1
f'  = u' v + u v'
f' (x) =  {(8x-4)(x+2) + (2x-1)²(1)}
f' (x) = (8x²- 12x - 8 + 4x² -  4x +1
f '(x) =  12x² - 16x -7

cara 2
f(x)= (2x-1)²(x+2)
f(x)= (4x² - 4x + 1)(x + 2)
f(x) = 4x³ + 8x² - 4x² - 8x  + x + 2
f(x)= 4x³ + 4x² - 7x + 2
f' (x) = 12 x² +8x - 7