[tex] \frac{x-5}{2x} = -4 x \neq 0[/tex] tolong cara yang jelas

x-5 / 2x = -4x
x=/ 0
x-5 = -4x (2x)
x-5 = -8x²
8x²+x-5 =0
-b +/- √b² - 4ac / 2a
= (-1 +/- √1 - 4(8)(-5)) / 2
= -1+/- √1+161 /2

x1 = (-1 + √162)/2
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x2= (-1-√162) /2