Integral 1 Sampai 3 (2x+1) dx ?

Materi Integral

(3 # 1) int (2x+1) dx
= (3 # 1) (x^2 + x)
= (3^2 + 3) - (1^2 + 1) = 12 - 2 = 10

1∫ 3 (2x+1) dx
[x² + x] 3 - [x² +x] 1
[3² +3 ] - [1² +1]
[12-2]
= 10