Tentukan penyelesaian dari persamaan berikut: A.2(a+3)=12 B.5(2R-3)=5 C.3+(P+6)=2(P-3)

A.2(a+3)=12
2a+6=12
2a=6
a=3

B.5(2R)-3)=5
10R-15=5
10R=20
R=2

C.3(P+6)=2(P-3)
3P+18=2P-6
3P-2P=-6-18
P=-24

a. 2(a+3) = 12
= 2a + 6 = 12
=2a = 12 -6
=2a = 6
= a = 6/2
= a = 3

b. 5(2r-3) = 5
= 10r - 15 = 5
= 10r = 5 +15
= 10r = 20
= r = 20/10
= r = 2

c. 3+(p+6) = 2(p-3)
= 3p + 18 = 2p-6
= 3p - 2p = -6 - 18
= -p = -24
= p = -24 /-1
= p = 24