(2⁴×2^7×3²/3)-²=…………………

Jawaban: 2^-22 * 3^-2
Baca: 2 pangkat minus 22 dikali dengan 3 pangkat minus 2
Wish you luck~ ;)

(2^4 × 2^7 × 3^3 / 3)^-2
= (2^(4+7) × 3^(3-1))^-2
= (2^11 × 3^2)^-2
= 2^(11×-2) × 3^(2×-2)
= 2^-22 × 3^-4
= 1 / (2^22 × 3^4)