#nomor1 |2x| = 4 #nomor2 |x-3| = 5 #nomor3 -3x|5-y| = -6 tolong dibantu beserta caranya ya
Matematika
ngel99
Pertanyaan
#nomor1 |2x| = 4 #nomor2 |x-3| = 5 #nomor3 -3x|5-y| = -6 tolong dibantu beserta caranya ya
1 Jawaban
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1. Jawaban 4LL
Nomor 1
|2x| = 4
(2x)² = 4²
4x² - 16 = 0
4(x² - 4) = 0
x² - 4 = 0
(x - 2)(x + 2) = 0
x = 2 dan x= -2
HP {2 , -2}
Nomor 2
|x - 3| = 5
(x - 3)² = 5²
x² - 6x + 9 = 25
x² - 6x - 16 = 0
(x - 8)(x + 2) = 0
x = 8 dan x = -2
HP {8 , -2}
Nomor 3
-3|5 - y| = -6
(5 - y)² = 2²
25 - 10y + y² = 4
y² - 10y + 21 = 0
(y - 7)(y - 3) = 0
y = 7 dan y = 3
HP {7 , 3}
semoga berguna +_+