Matematika

Pertanyaan

#nomor1 |2x| = 4 #nomor2 |x-3| = 5 #nomor3 -3x|5-y| = -6 tolong dibantu beserta caranya ya

1 Jawaban

  • Nomor 1
    |2x| = 4
    (2x)² = 4²
    4x² - 16 = 0
    4(x² - 4) = 0
    x² - 4 = 0
    (x - 2)(x + 2) = 0
    x = 2 dan x= -2

    HP {2 , -2}

    Nomor 2
    |x - 3| = 5
    (x - 3)² = 5²
    x² - 6x + 9 = 25
    x² - 6x - 16 = 0
    (x - 8)(x + 2) = 0
    x = 8 dan x = -2

    HP {8 , -2}

    Nomor 3
    -3|5 - y| = -6
    (5 - y)² = 2²
    25 - 10y + y² = 4
    y² - 10y + 21 = 0
    (y - 7)(y - 3) = 0
    y = 7 dan y = 3

    HP {7 , 3}

    semoga berguna +_+


Pertanyaan Lainnya