Matematika

Pertanyaan

Nomor 3,4,9 tolong yak pake cara
Nomor 3,4,9 tolong yak pake cara

1 Jawaban

  • 3) tan a = a/x
    sisi depan a
    sisi samping x
    sisi miring √(a²+x²)
    x/√(a²+x²) = samping/miring = cos a
    pilihan B
    4) (1+sin a)(1-sin a) / (1+cos a)(1-cos a)
    = (1 - sin²a)/(1-cos²a)
    = cos²a/sin²a
    = cotan²a
    = 7/8
    9) (sin a + cos a)² + (sin a - cos a)²
    = sin²a + 2.sin a.cos a + cos²a + sin²a - 2.sin a.cos a + cos²a
    = 2sin²a + 2cos²a
    = 2(sin²a + cos²a)
    = 2(1)
    = 2