Matematika

Pertanyaan

akar98+akar50-akar8-akar72 jdi brp ?

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  • [tex]= \sqrt{98} + \sqrt{50} - \sqrt{8} - \sqrt{72} \\ = \sqrt{49X2} + \sqrt{25X2} - \sqrt{4X2} - \sqrt{36X2} \\ =( \sqrt[2]{49} X \sqrt{2} ) + ( \sqrt[2]{25} X \sqrt{2} )-( \sqrt[2]{4} X \sqrt{2} )-( \sqrt[2]{36}X \sqrt{2} ) \\ =7 \sqrt{2} + 5 \sqrt{2} -2 \sqrt{2} -6 \sqrt{2} \\ =12 \sqrt{2} -12 \sqrt{2} \\ =\sqrt{2} [/tex]

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