didalam 400 ml larutan amonia, terlarut 3,4 gr NH3(Ar N=14, H:1) hitunglah fraksi mol larutan

n NH3 = 3.4/17 = 0.2 mol
n air = 400/18 = 22.2 mol
Xt = nt/(nt + np) 
Xt = 0.2 / ( 0.2 + 22.2 ) = 0.2/22.4 = 0.008928
Xt = 8.9 x 10^-3