1.f(x)=(x²+1)(x+5) 2.f(x)=(x+1)(x³+5)

Turunan

q. f(x) = (x² +1)(x+5)
f = u v
f' = u'v + uv'
u = x² + 1 --> u'= 2x
v = x+5  --> v' = 1

f' (x)= 2x(x+5) + (x²+1)(1)
f'(x)= 2x²+10x + x² +1
f '(x) = 3x² + 10x + 1


2. f(x)= (x+1)(x³+5)
u = x+ 1  --> u'= 1
v = x³+5 --> v'= 3x²

f ' = u'v + uv'
f'(x)= 1(x³+5) + (x+1)(3x²)
f'(x)= x³+5 + 3x³ + 3x²
f'(x)= 4x³ + 3x² + 5