Matematika

Pertanyaan

tolong bantu yaaaaaaaaaaaaaaaa, terima kasih
tolong bantu yaaaaaaaaaaaaaaaa, terima kasih

2 Jawaban

  • Penyelesaian:

    ( (8m^-9) (n^-2) / (64m^-6) (n) )^-1
    = ((1/8) (m^-3) (n^-3))^-1
    = 8(m^3)(n^3)
    = (2^3)(m^3)(n^3)
    = (2mn)^3 (E).
  • [(8m^-9 . n^-2)/(64 m^-6 n)]^-1
    = [(64 m^-6 n)/(8 m^-9 n^-2)]^1
    = 64/8 . m^(-6 - (-9)) . n^(1 - (-2))
    = 8 . m^(-6 + 9) . n^(1 + 2)
    = 2^3 . m^3 . n^3
    = (2mn)^3