(nomor1)40×45+3.200÷(-8)+(-14)×90= (nomor2)400×(-7)-6.000÷40+3.000= tolong di jawab ya ini pribadi

Question

Matematika Diposting : 2017-07-23 Diupdate : 2022-07-26 NurAzida2005

Pertanyaan

(nomor1)40×45+3.200÷(-8)+(-14)×90=
(nomor2)400×(-7)-6.000÷40+3.000=
tolong di jawab ya ini pribadi

Answer 1

1. 40x45+3.200÷(-8)+(-14)x90
= 1800+(-400)+(-1260)
= 1400+(-1260)
= 140
2. 400x(-7)-6.000÷40+3.000
= -2800-150+3000
= -2950+3000
= 50