tentukanfraksi mol zat terlarut dan pelarut jika ke dalam 90 gram air dilarutkan 15 gram asam cuka (ch3coooh)?

N pelarut = gr / Mr air = 90/18 = 5 mol

N terlarur = gr / Mr ch3cooh = 15/60 = 4mol

X terlarut = Nt / (Nt +Np)
=4/9

X pelarur = Np / (Nt+Np) = 5/9