persamaan nilai mutlak 3 |x-1| -2 |x+1| = 0

3 |x-1| -2 |x+1| = 0
|3x-3| |-2x-2| = 0
3x-3 -2x-2 = 0
3x-2x =0+3+2
x =5

pembuktian
3 |x-1| -2 |x+1| = 0
3 |5-1| -2 |5+1| =
3 | 4 | -2 | 6 | =
3.4 - 2.6 =
12 -12 =0