Integral 4x³ +2x² dx = Integral 4x pangkat6 +7x³ - 5x dx= Integral (³√x²-⁴√x³) dx = Integral (x³-1)² per x³ dx=

Jawab:

Integral :

Rumus dasar integral tak tentu

[tex] {\boxed{\ \tt   \int x {}^{n}dx =  \frac{1}{n + 1}  x {}^{n+ 1}  + C }} [/tex]

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# Soal 1

∫ 4x³ + 2x² dx

= 4/(3 + 1) x^{3 + 1} + 2/(2 + 1) x^{2 + 1} + C

= x⁴ + 2/3 x³ + C

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# Soal 2

∫ 4x⁶ + 7x³ - 5x dx

= 4/(6 + 1) x^{6 + 1} + 7/(3 + 1) x^{3 + 1} - 5/(1 + 1) x^{1 + 1} + C

= 4/7 x⁷ + 7/4 x⁴ - 5/2 x² + C

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# Soal 3

∫ (³√x² - ⁴√x³) dx =

∫ (x^{2/3} - x^{3/4}) dx

= 1/(2/3 + 1) x^{2/3 + 1} - 1/(3/4 + 1) x^{3/4 + 1} + C

= 1/(5/ 3) x^{5/3} - 1/(7/4) x^{7/4} + C

= 3/5 x^{5/3} - 4/7 x^{7/4} + C

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# Soal 4

∫ (x³ - 1)² / x³ dx

∫ (x⁶ - 2x³ + 1) / x³ dx

∫ (x³ - 2 + x⁻³) dx

= 1/4 x⁴ - 2x - 1/2 x⁻² + C

= x⁴/4 - x²/2 - 2x + C

••••••••••••••••••••••♪♪♪♪•••••••••••••••••••••

Detail jawaban

♬ Mapel: Matematika

♬ Kelas: XI

♬ Materi: Bab 10 - Integral tak tentu

♬ Kata kunci: integral

♬ Kode Soal: 2

♬ Kode Kategorisasi: 11.2.10

semoga membantu,

met belajar skuy :)

—Yan

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