tentukan fraksimol zat terlarut dan pelarut dalam? A.larutan tersebut 15 gram CH3COOH dan 180 gram air? B.larutan 10% massa NaOH? C.larutan 1 Molal glukosa

A. Mol CH3COOH = 15/60 =0.25 mol
Mol H2O = 18 / 180 = 0.1
Xt = 0.25 / 0.25 + 0.1 =0.71
Xp = 1-0.71 = 0.29
B. Mol NaOH = 10/40 =0.25
Mol H2O = 90 / 18 = 5
Xt = 0.25 / 0.25 + 5 = 0.047
Xp = 1-0.047 = 0.95
C. m = gr/mr × 1000/p
1 = gr / p × 1000/180
18 = % × 100
Gr = 18%
= 18 gr
Mol C6H12O6 = 18/ 180 = 0.1
Mol H2O = 82 / 18 = 4.5
Xt = 0.1/ 4.5 + 0.1 = 0.02
Xp = 1 - 0.02 = 0.98

* Xt = fraksi mol zat terlarut
Xp = fraksi mol zat pelarut
Xt = mol terlarut / mol terlarut + mol pelarut
Xp = 1- Xt
**Yg C mgkn slh..sorry ya..